I want to open another form based on another form value in Access -


Hello, I have a list that is a drop list value. "Transparent", "Promo", and "New" if the user selects the transfer or promo, then another form call will open the old information and in that form it will move the same ID, the user who entered the first time did. Anyone can help me please

  dcmd OpenForm strMyFormName, "ID =" & amp; IntMyID   

You can use the value by using code in intMyID . OpenArgs .



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