c - Operator Precedence - Expression Evaluation -

I get the output as 1 for the following code snippets. I want to know how it came?

  zero main () {int x = 10, y = 20, z = 5, i; I = x's & lt; Y & lt; Z; Printf ("% d", i); }    
 
 
  i = x & lt; Y & lt; Z; ,  i = (x & lt; y) & lt; Z is interpreted as  which in turn  i = 1 & lt; Z , which evaluates for 1.