cpu registers - How to print -0x4(%rbp) in gdb? -


Disassembly contains such code: 

  movl $ 0x6, -0x4 (% rbp) )   
 I try to print the value like this but fails:  
  (gdb) p 0x4 (% esp) expression in one Syntax error,% esp) '. (GDB) number 0x4 + $ esp for logic arithmetic operations, no number or bullion.   
 How to print it correctly?  
  
 
 
 It looks like you, working with 64 bit code, in which case you just need Is like:  
  (gdb) p $ rbp-0x4 $ 1 = (zero *) 0x7fff5fbff71c   
 If you want to see that in fact  at  is at this address, then you must enter the  zero *  address, e.g.  
  (Gdb) p / x * (int *) ($ rbp-0x4) $ 2 = 0x7fff   
 Or in a nutshell,  Instead of x , use  p , such as  
  (gdb) x / w $ rbp-0x4 0x7fff5fbff71c: 0x00007fff

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